What is x^2+y^2-22x+20y+196=0 ?

The solution to x^2+y^2-22x+20y+196=0 is Circle with (a,b)=(11,-10),r=5

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x^2+y^2-22x+20y+196=0

x^{2} + y^{2} - 22 x + 20 y + 196 = 0

(a, b) = (11, - 10), r = 5

Solution steps

x^{2} + y^{2} - 22 x + 20 y + 196 = 0

Rewrite

x^{2} + y^{2} - 22 x + 20 y + 196 = 0

in the form of the standard circle equation

(x - 11)^{2} + (y - (- 10))^{2} = 5^{2}

Therefore the circle properties are:

(a, b) = (11, - 10), r = 5

What is x^2+y^2-22x+20y+196=0 ?
The solution to x^2+y^2-22x+20y+196=0 is Circle with (a,b)=(11,-10),r=5