What is x^2+y^2-10x+12y=3 ?

The solution to x^2+y^2-10x+12y=3 is Circle with (a,b)=(5,-6),r=8

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x^2+y^2-10x+12y=3

x^{2} + y^{2} - 10 x + 12 y = 3

(a, b) = (5, - 6), r = 8

Solution steps

x^{2} + y^{2} - 10 x + 12 y = 3

Rewrite

x^{2} + y^{2} - 10 x + 12 y = 3

in the form of the standard circle equation

(x - 5)^{2} + (y - (- 6))^{2} = 8^{2}

Therefore the circle properties are:

(a, b) = (5, - 6), r = 8

x^{2} + y^{2} + 4 x + 2 y = 1

x^{2} + y^{2} - 22 x + 20 y + 196 = 0

x^{2} + y^{2} + 3 x - 5 y + \frac{25}{4} = 0

4 x^{2} + 4 y^{2} - 4 x + 12 y + 9 = 0

x^{2} + y^{2} + \frac{1}{2} x - \frac{3}{2} y = \frac{71}{16}

What is x^2+y^2-10x+12y=3 ?
The solution to x^2+y^2-10x+12y=3 is Circle with (a,b)=(5,-6),r=8