What is 9x^2+9y^2-24x+84y+65=0 ?

The solution to 9x^2+9y^2-24x+84y+65=0 is Circle with (a,b)=(4/3 ,-14/3),r= 7/(sqrt(3))

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9x^2+9y^2-24x+84y+65=0

9 x^{2} + 9 y^{2} - 24 x + 84 y + 65 = 0

(a, b) = (\frac{4}{3}, - \frac{14}{3}), r = \frac{7}{3}

Solution steps

9 x^{2} + 9 y^{2} - 24 x + 84 y + 65 = 0

Rewrite

9 x^{2} + 9 y^{2} - 24 x + 84 y + 65 = 0

in the form of the standard circle equation

(x - \frac{4}{3})^{2} + (y - (- \frac{14}{3}))^{2} = (\frac{7}{3})^{2}

Therefore the circle properties are:

(a, b) = (\frac{4}{3}, - \frac{14}{3}), r = \frac{7}{3}

(x - 1.5)^{2} + (y - 1)^{2} = 3

x^{2} + y^{2} - 6 x + 8 y - 12 = 0

5 (x^{2} - 1.8) + 5 (y^{2} - 28) + 26 = 0

x^{2} + y^{2} + 10 x + 6 y + 18 = 0 x

x^{2} + y^{2} - 2 x - 6 y = - 6

What is 9x^2+9y^2-24x+84y+65=0 ?
The solution to 9x^2+9y^2-24x+84y+65=0 is Circle with (a,b)=(4/3 ,-14/3),r= 7/(sqrt(3))