What is x^2+y^2-20x+8y+116=sqrt(200) ?

The solution to x^2+y^2-20x+8y+116=sqrt(200) is Circle with (a,b)=(10,-4),r=sqrt(5)*2^{3/4}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^2+y^2-20x+8y+116=sqrt(200)

x^{2} + y^{2} - 20 x + 8 y + 116 = 200

(a, b) = (10, - 4), r = 5 \cdot 2^{\frac{3}{4}}

Solution steps

x^{2} + y^{2} - 20 x + 8 y + 116 = 200

Rewrite

x^{2} + y^{2} - 20 x + 8 y + 116 = 200

in the form of the standard circle equation

(x - 10)^{2} + (y - (- 4))^{2} = (5 \cdot 2^{\frac{3}{4}})^{2}

Therefore the circle properties are:

(a, b) = (10, - 4), r = 5 \cdot 2^{\frac{3}{4}}

(x - 4)^{2} + (y - 1)^{2} = 36

x^{2} + 6 x + 9 + y^{2} - 10 y - 25 = 36

(x - 3)^{2} + (y + 7)^{2} = 9

y^{2} + x^{2} - 10 x + 4 y - 7 = 0

x (x - 12) + y (y + 2) = 12

What is x^2+y^2-20x+8y+116=sqrt(200) ?
The solution to x^2+y^2-20x+8y+116=sqrt(200) is Circle with (a,b)=(10,-4),r=sqrt(5)*2^{3/4}