What is (x-3)^2+(y+7)^2=9 ?

The solution to (x-3)^2+(y+7)^2=9 is Circle with (a,b)=(3,-7),r=3

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(x-3)^2+(y+7)^2=9

(x - 3)^{2} + (y + 7)^{2} = 9

(a, b) = (3, - 7), r = 3

Solution steps

(x - 3)^{2} + (y + 7)^{2} = 9

Rewrite

(x - 3)^{2} + (y + 7)^{2} = 9

in the form of the standard circle equation

(x - 3)^{2} + (y - (- 7))^{2} = 3^{2}

Therefore the circle properties are:

(a, b) = (3, - 7), r = 3

What is (x-3)^2+(y+7)^2=9 ?
The solution to (x-3)^2+(y+7)^2=9 is Circle with (a,b)=(3,-7),r=3