What is (x^2+4x)+(y^2-10y)=-4 ?

The solution to (x^2+4x)+(y^2-10y)=-4 is Circle with (a,b)=(-2,5),r=5

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(x^2+4x)+(y^2-10y)=-4

(x^{2} + 4 x) + (y^{2} - 10 y) = - 4

(a, b) = (- 2, 5), r = 5

Solution steps

x^{2} + 4 x + (y^{2} - 10 y) = - 4

Rewrite

x^{2} + 4 x + (y^{2} - 10 y) = - 4

in the form of the standard circle equation

(x - (- 2))^{2} + (y - 5)^{2} = 5^{2}

Therefore the circle properties are:

(a, b) = (- 2, 5), r = 5

What is (x^2+4x)+(y^2-10y)=-4 ?
The solution to (x^2+4x)+(y^2-10y)=-4 is Circle with (a,b)=(-2,5),r=5