Solution
Solution
Solution steps
Rewrite in the form of the standard circle equation
Therefore the circle properties are:
Graph
Popular Examples
x(x-12)+y(y+2)=12(x^2+4x)+(y^2-10y)=-4(4(x+5/2)^2)/(45)+(4(y-2)^2)/(45)=1x^2-18x+29+y^2=03x^2>12-3y^2
Frequently Asked Questions (FAQ)
What is y^2+x^2-10x+4y-7=0 ?
The solution to y^2+x^2-10x+4y-7=0 is Circle with (a,b)=(5,-2),r=6