What is (x+8)^2+(y-4)^2=20 ?

The solution to (x+8)^2+(y-4)^2=20 is Circle with (a,b)=(-8,4),r=sqrt(20)

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(x+8)^2+(y-4)^2=20

(x + 8)^{2} + (y - 4)^{2} = 20

(a, b) = (- 8, 4), r = 20

Solution steps

(x + 8)^{2} + (y - 4)^{2} = 20

Rewrite

(x + 8)^{2} + (y - 4)^{2} = 20

in the form of the standard circle equation

(x - (- 8))^{2} + (y - 4)^{2} = (20)^{2}

Therefore the circle properties are:

(a, b) = (- 8, 4), r = 20

What is (x+8)^2+(y-4)^2=20 ?
The solution to (x+8)^2+(y-4)^2=20 is Circle with (a,b)=(-8,4),r=sqrt(20)