What is x^2+y^2+2x-6y+8=0 ?

The solution to x^2+y^2+2x-6y+8=0 is Circle with (a,b)=(-1,3),r=sqrt(2)

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x^2+y^2+2x-6y+8=0

x^{2} + y^{2} + 2 x - 6 y + 8 = 0

(a, b) = (- 1, 3), r = 2

Solution steps

x^{2} + y^{2} + 2 x - 6 y + 8 = 0

Rewrite

x^{2} + y^{2} + 2 x - 6 y + 8 = 0

in the form of the standard circle equation

(x - (- 1))^{2} + (y - 3)^{2} = (2)^{2}

Therefore the circle properties are:

(a, b) = (- 1, 3), r = 2

x^{2} + y^{2} + 6 x - 4 y - 51 = 0

x^{2} + y^{2} - 10 x + 16 y + 25 = 0

x^{2} + y^{2} + 12 x + 14 y + 85 = 4

12 x^{2} + 12 y^{2} + 12 x - 24 y + 3 = 0

(x + \frac{9}{4})^{2} = \frac{13}{2} - (y - 8)^{2}

What is x^2+y^2+2x-6y+8=0 ?
The solution to x^2+y^2+2x-6y+8=0 is Circle with (a,b)=(-1,3),r=sqrt(2)