What is x^2+y^2-10x+16y+25=0 ?

The solution to x^2+y^2-10x+16y+25=0 is Circle with (a,b)=(5,-8),r=8

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x^2+y^2-10x+16y+25=0

x^{2} + y^{2} - 10 x + 16 y + 25 = 0

(a, b) = (5, - 8), r = 8

Solution steps

x^{2} + y^{2} - 10 x + 16 y + 25 = 0

Rewrite

x^{2} + y^{2} - 10 x + 16 y + 25 = 0

in the form of the standard circle equation

(x - 5)^{2} + (y - (- 8))^{2} = 8^{2}

Therefore the circle properties are:

(a, b) = (5, - 8), r = 8

x^{2} + y^{2} + 12 x + 14 y + 85 = 4

12 x^{2} + 12 y^{2} + 12 x - 24 y + 3 = 0

(x + \frac{9}{4})^{2} = \frac{13}{2} - (y - 8)^{2}

x^{2} + y^{2} - 36 x + 12 y + 80 = 0

(x - 4)^{2} + (y + 1)^{2} = 4

What is x^2+y^2-10x+16y+25=0 ?
The solution to x^2+y^2-10x+16y+25=0 is Circle with (a,b)=(5,-8),r=8