What is x^2+y^2-4x-8y+19=0 ?

The solution to x^2+y^2-4x-8y+19=0 is Circle with (a,b)=(2,4),r=1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

x^2+y^2-4x-8y+19=0

x^{2} + y^{2} - 4 x - 8 y + 19 = 0

(a, b) = (2, 4), r = 1

Solution steps

x^{2} + y^{2} - 4 x - 8 y + 19 = 0

Rewrite

x^{2} + y^{2} - 4 x - 8 y + 19 = 0

in the form of the standard circle equation

(x - 2)^{2} + (y - 4)^{2} = 1^{2}

Therefore the circle properties are:

(a, b) = (2, 4), r = 1

What is x^2+y^2-4x-8y+19=0 ?
The solution to x^2+y^2-4x-8y+19=0 is Circle with (a,b)=(2,4),r=1