What is x^2+4x+y^2+8y+155/9 =0 ?

The solution to x^2+4x+y^2+8y+155/9 =0 is Circle with (a,b)=(-2,-4),r= 5/3

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x^2+4x+y^2+8y+155/9 =0

x^{2} + 4 x + y^{2} + 8 y + \frac{155}{9} = 0

(a, b) = (- 2, - 4), r = \frac{5}{3}

Solution steps

x^{2} + 4 x + y^{2} + 8 y + \frac{155}{9} = 0

Rewrite

x^{2} + 4 x + y^{2} + 8 y + \frac{155}{9} = 0

in the form of the standard circle equation

(x - (- 2))^{2} + (y - (- 4))^{2} = (\frac{5}{3})^{2}

Therefore the circle properties are:

(a, b) = (- 2, - 4), r = \frac{5}{3}

(x - 3)^{2} + y^{2} = 112

x^{(2)} + y^{(2)} - 2 x - 4 y - 5 = 0

x^{2} + x + y^{2} - 65 y = 1

(x + 4)^{2} + (y - 7)^{2} = 64

x^{2} + y^{2} + 10 x - 2 y + 25 = 0

What is x^2+4x+y^2+8y+155/9 =0 ?
The solution to x^2+4x+y^2+8y+155/9 =0 is Circle with (a,b)=(-2,-4),r= 5/3