What is 4x^2+4y^2-56x+8y+56=0 ?

The solution to 4x^2+4y^2-56x+8y+56=0 is Circle with (a,b)=(7,-1),r=6

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4x^2+4y^2-56x+8y+56=0

4 x^{2} + 4 y^{2} - 56 x + 8 y + 56 = 0

(a, b) = (7, - 1), r = 6

Solution steps

4 x^{2} + 4 y^{2} - 56 x + 8 y + 56 = 0

Rewrite

4 x^{2} + 4 y^{2} - 56 x + 8 y + 56 = 0

in the form of the standard circle equation

(x - 7)^{2} + (y - (- 1))^{2} = 6^{2}

Therefore the circle properties are:

(a, b) = (7, - 1), r = 6

x^{2} + (y - 2)^{2} = 28

(x + 7)^{2} + (y - 3)^{2} = 64

9 x^{2} + 36 x + 9 y^{2} + 72 y + 155 = 0

2 x^{2} + 2 y^{2} - 17 x = 0

x^{2} + y^{2} + 8 x + 6 y - 11 = 0

What is 4x^2+4y^2-56x+8y+56=0 ?
The solution to 4x^2+4y^2-56x+8y+56=0 is Circle with (a,b)=(7,-1),r=6