What is (x+7)^2+(y-3)^2=64 ?

The solution to (x+7)^2+(y-3)^2=64 is Circle with (a,b)=(-7,3),r=8

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(x+7)^2+(y-3)^2=64

(x + 7)^{2} + (y - 3)^{2} = 64

(a, b) = (- 7, 3), r = 8

Solution steps

(x + 7)^{2} + (y - 3)^{2} = 64

Rewrite

(x + 7)^{2} + (y - 3)^{2} = 64

in the form of the standard circle equation

(x - (- 7))^{2} + (y - 3)^{2} = 8^{2}

Therefore the circle properties are:

(a, b) = (- 7, 3), r = 8

9 x^{2} + 36 x + 9 y^{2} + 72 y + 155 = 0

2 x^{2} + 2 y^{2} - 17 x = 0

x^{2} + y^{2} + 8 x + 6 y - 11 = 0

x^{2} + y^{2} = 28

x^{2} + y^{2} + 2 x - 4 y + 2 = 0

What is (x+7)^2+(y-3)^2=64 ?
The solution to (x+7)^2+(y-3)^2=64 is Circle with (a,b)=(-7,3),r=8