What is 9x^2+36x+9y^2+72y+155=0 ?

The solution to 9x^2+36x+9y^2+72y+155=0 is Circle with (a,b)=(-2,-4),r= 5/3

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9x^2+36x+9y^2+72y+155=0

9 x^{2} + 36 x + 9 y^{2} + 72 y + 155 = 0

(a, b) = (- 2, - 4), r = \frac{5}{3}

Solution steps

9 x^{2} + 36 x + 9 y^{2} + 72 y + 155 = 0

Rewrite

9 x^{2} + 36 x + 9 y^{2} + 72 y + 155 = 0

in the form of the standard circle equation

(x - (- 2))^{2} + (y - (- 4))^{2} = (\frac{5}{3})^{2}

Therefore the circle properties are:

(a, b) = (- 2, - 4), r = \frac{5}{3}

2 x^{2} + 2 y^{2} - 17 x = 0

x^{2} + y^{2} + 8 x + 6 y - 11 = 0

x^{2} + y^{2} = 28

x^{2} + y^{2} + 2 x - 4 y + 2 = 0

4 x^{2} + 4 y^{2} + 12 x - 4 y - 90 = 0

What is 9x^2+36x+9y^2+72y+155=0 ?
The solution to 9x^2+36x+9y^2+72y+155=0 is Circle with (a,b)=(-2,-4),r= 5/3