What is x^2+(y-2)^2=28 ?

The solution to x^2+(y-2)^2=28 is Circle with (a,b)=(0,2),r=sqrt(28)

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x^2+(y-2)^2=28

x^{2} + (y - 2)^{2} = 28

(a, b) = (0, 2), r = 28

Solution steps

x^{2} + (y - 2)^{2} = 28

Rewrite

x^{2} + (y - 2)^{2} = 28

in the form of the standard circle equation

(x - 0)^{2} + (y - 2)^{2} = (28)^{2}

Therefore the circle properties are:

(a, b) = (0, 2), r = 28

(x + 7)^{2} + (y - 3)^{2} = 64

9 x^{2} + 36 x + 9 y^{2} + 72 y + 155 = 0

2 x^{2} + 2 y^{2} - 17 x = 0

x^{2} + y^{2} + 8 x + 6 y - 11 = 0

x^{2} + y^{2} = 28

What is x^2+(y-2)^2=28 ?
The solution to x^2+(y-2)^2=28 is Circle with (a,b)=(0,2),r=sqrt(28)