What is the critical f(x)=x^3-3x^2-9x+2 ?

The critical f(x)=x^3-3x^2-9x+2 is x=-1,x=3

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critical f(x)=x^3-3x^2-9x+2

critical points

f (x) = x^{3} - 3 x^{2} - 9 x + 2

x = - 1, x = 3

Solution steps

x^{3} - 3 x^{2} - 9 x + 2

Find where

f^{'} (x)

is equal to zero or undefined

x = - 1, x = 3

Identify critical points not in

f (x)

domain

Domain of

x^{3} - 3 x^{2} - 9 x + 2 : - \infty < x < \infty

All critical points are in domain

x = - 1, x = 3

f (x) = \frac{( x - 4 )}{x - 2}

m = - 7, (1, 1)

f (x) = \frac{- 1}{( x + 3 ) ^{2}} - 4

\frac{1}{6} x^{3} - 4

y = 3 x + 3, (3, 2)

What is the critical f(x)=x^3-3x^2-9x+2 ?
The critical f(x)=x^3-3x^2-9x+2 is x=-1,x=3