What is the range of f(x)=((x-4))/(x-2) ?

The range of f(x)=((x-4))/(x-2) is f(x) 1

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range of f(x)=((x-4))/(x-2)

range

f (x) = \frac{( x - 4 )}{x - 2}

f (x) < 1 or f (x) > 1

Interval Notation

(- \infty, 1) \cup (1, \infty)

Solution steps

The function range is the combined domain of the inverse functions

Find the inverse function(s) of:

\frac{x - 4}{x - 2}

Inverse of

\frac{x - 4}{x - 2} : \frac{- 4 + 2 x}{x - 1}

\frac{- 4 + 2 x}{x - 1}

Find the domain of each inverse function

Domain of

\frac{- 4 + 2 x}{x - 1} : x < 1 or x > 1

Combine the intervals

f (x) < 1 or f (x) > 1

m = - 7, (1, 1)

f (x) = \frac{- 1}{( x + 3 ) ^{2}} - 4

\frac{1}{6} x^{3} - 4

y = 3 x + 3, (3, 2)

f (x) = - 5 x - 3

What is the range of f(x)=((x-4))/(x-2) ?
The range of f(x)=((x-4))/(x-2) is f(x)<1\lor f(x)>1