What is the perpendicular y=3x+3,(3,2) ?

The perpendicular y=3x+3,(3,2) is y=-1/3 x+3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

perpendicular y=3x+3,(3,2)

perpendicular

y = 3 x + 3, (3, 2)

y = - \frac{1}{3} x + 3

Solution steps

Find the line

y = mx + b

perpendicular to

y = 3 x + 3

that passes through

(3, 2)

Find the slope of

y = 3 x + 3 : m = 3

Compute the slope of the perpendicular line:

m_{p} = - \frac{1}{3}

Find the line with slope m=

- \frac{1}{3}

and passing through

(3, 2) : y = - \frac{1}{3} x + 3

y = - \frac{1}{3} x + 3

f (x) = - 5 x - 3

2 x^{2} + 5 x - 3

15 x - 3 y = 1

f (x) = \frac{( 2 x ^{2} )}{( 4 x ^{2} - 1 )}

\frac{x + 2}{3 x - 5}

What is the perpendicular y=3x+3,(3,2) ?
The perpendicular y=3x+3,(3,2) is y=-1/3 x+3