What is the asymptotes of f(x)=((2x^2))/((4x^2-1)) ?

The asymptotes of f(x)=((2x^2))/((4x^2-1)) is Vertical: x=-1/2 ,x= 1/2 ,Horizontal: y= 1/2

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asymptotes of f(x)=((2x^2))/((4x^2-1))

asymptotes

f (x) = \frac{( 2 x ^{2} )}{( 4 x ^{2} - 1 )}

Vertical : x = - \frac{1}{2}, x = \frac{1}{2}, Horizontal : y = \frac{1}{2}

Solution steps

Vertical asymptotes of

\frac{2 x ^{2}}{4 x ^{2} - 1} : x = - \frac{1}{2}, x = \frac{1}{2}

Horizontal Asymptotes of

\frac{2 x ^{2}}{4 x ^{2} - 1} : y = \frac{1}{2}

Slant Asymptotes of

\frac{2 x ^{2}}{4 x ^{2} - 1} :

None

Vertical : x = - \frac{1}{2}, x = \frac{1}{2}, Horizontal : y = \frac{1}{2}

\frac{x + 2}{3 x - 5}

f (x) = x - \frac{5}{g ( x )} (x) = x + 6

\frac{3 + x}{x - 2}

9 - x

f (x) = \frac{1}{17 - t}

What is the asymptotes of f(x)=((2x^2))/((4x^2-1)) ?
The asymptotes of f(x)=((2x^2))/((4x^2-1)) is Vertical: x=-1/2 ,x= 1/2 ,Horizontal: y= 1/2