What is the domain of f(x)=sqrt((-2x+8))-6 ?

The domain of f(x)=sqrt((-2x+8))-6 is x<= 4

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domain of f(x)=sqrt((-2x+8))-6

domain

f (x) = (- 2 x + 8) - 6

x \leq 4

Interval Notation

(- \infty, 4]

Solution steps

Find non-negative values for radicals:

x \leq 4

The function domain

x \leq 4

\frac{4 x + 5}{3 x - 4}

f (x) = x^{3} - 3 x^{2} - 9 x + 2

f (x) = \frac{( x - 4 )}{x - 2}

m = - 7, (1, 1)

f (x) = \frac{- 1}{( x + 3 ) ^{2}} - 4

What is the domain of f(x)=sqrt((-2x+8))-6 ?
The domain of f(x)=sqrt((-2x+8))-6 is x<= 4