What is the inverse of (e^x-e^{-x})/2 ?

The inverse of (e^x-e^{-x})/2 is ln(x+sqrt(x^2+1)),ln(x-sqrt(x^2+1))

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inverse of (e^x-e^{-x})/2

inverse

\frac{e ^{x} - e ^{- x}}{2}

ln (x + x^{2} + 1), ln (x - x^{2} + 1)

Solution steps

y = \frac{e ^{x} - e ^{- x}}{2}

Replace

x

with

y

x = \frac{e ^{y} - e ^{- y}}{2}

Solve for

y, x = \frac{e ^{y} - e ^{- y}}{2}

ln (x + x^{2} + 1), ln (x - x^{2} + 1)

f (x) = \frac{7 x}{2 x - 3}

\frac{5}{x}

f (x) = (- 2 x + 8) - 6

\frac{4 x + 5}{3 x - 4}

f (x) = x^{3} - 3 x^{2} - 9 x + 2

What is the inverse of (e^x-e^{-x})/2 ?
The inverse of (e^x-e^{-x})/2 is ln(x+sqrt(x^2+1)),ln(x-sqrt(x^2+1))