extreme y=x(20-2x)(0.5*45-x)

Lösung

extrempunkte

y = x (20 - 2 x) (0.5 \cdot 45 - x)

Maximum (\frac{5 ( 13 - 61 )}{6}, 892.18803 \dots), Minimum (\frac{5 ( 13 + 61 )}{6}, - 1313.48432 \dots)

Schritte zur Lösung

f^{'} (x) = 2 (3 x^{2} - 65 x + 225)

Intervalle finden:

Ansteigend

: - \infty < x < \frac{- 5 61 + 65}{6},

Absteigend

: \frac{- 5 61 + 65}{6} < x < \frac{5 61 + 65}{6},

Ansteigend

: \frac{5 61 + 65}{6} < x < \infty

Stecke

x = \frac{5 ( 13 - 61 )}{6}

x (20 - 2 x) (0.5 \cdot 45 - x) : 892.18803 \dots

Maximum (\frac{5 ( 13 - 61 )}{6}, 892.18803 \dots)

Stecke

x = \frac{5 ( 13 + 61 )}{6}

x (20 - 2 x) (0.5 \cdot 45 - x) : - 1313.48432 \dots

Minimum (\frac{5 ( 13 + 61 )}{6}, - 1313.48432 \dots)

Maximum (\frac{5 ( 13 - 61 )}{6}, 892.18803 \dots), Minimum (\frac{5 ( 13 + 61 )}{6}, - 1313.48432 \dots)

e x t re m e f (x, y) = \frac{x ^{3}}{3} - x y^{2} + \frac{2 y ^{5}}{5}

e x t re m e f (x) = - x^{2} + 7 x - 17

e x t re m e y = I n ∣ sec (5 x) + tan (5 x) ∣

e x t re m e f (x) = x^{3} - 3 x^{2} - 24 x + 5

e x t re m e f (x, y) = 12 x y - x^{3} - 6 y^{2}