What is the extreme f(x)=x^3-3x^2-24x+5 ?

The extreme f(x)=x^3-3x^2-24x+5 is Maximum(-2,33),Minimum(4,-75)

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extreme f(x)=x^3-3x^2-24x+5

extreme points

f (x) = x^{3} - 3 x^{2} - 24 x + 5

Maximum (- 2, 33), Minimum (4, - 75)

Solution steps

f^{'} (x) = 3 x^{2} - 6 x - 24

Find intervals:

Increasing

: - \infty < x < - 2,

Decreasing

: - 2 < x < 4,

Increasing

: 4 < x < \infty

Plug

x = - 2

into

x^{3} - 3 x^{2} - 24 x + 5 : 33

Maximum (- 2, 33)

Plug

x = 4

into

x^{3} - 3 x^{2} - 24 x + 5 : - 75

Minimum (4, - 75)

Maximum (- 2, 33), Minimum (4, - 75)

What is the extreme f(x)=x^3-3x^2-24x+5 ?
The extreme f(x)=x^3-3x^2-24x+5 is Maximum(-2,33),Minimum(4,-75)