What is the extreme 4x^2-2y^2+2xy ?

The extreme 4x^2-2y^2+2xy is Saddle(0,0)

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extreme 4x^2-2y^2+2xy

extreme points

4 x^{2} - 2 y^{2} + 2 x y

Saddle (0, 0)

Solution steps

Find the critical points:

(0, 0)

\frac{\partial ^{2} f}{\partial x ^{2}} = - 4

D (x, y) = - 36

Check the sign of at each critical point

Check critical point

(0, 0) :

Saddle

Saddle (0, 0)