extreme f(x)=x^3-3

解答

极值点

f (x) = x^{3} - 3

鞍点 (0, - 3)

求解步骤

f^{'} (x) = 3 x^{2}

Find intervals:

递增

: - \infty < x < 0,

递增

: 0 < x < \infty

将

x = 0

代入

x^{3} - 3 : - 3

鞍点 (0, - 3)

e x t re m e f (x, y) = 6 - \frac{x ^{2}}{3} - \frac{y ^{2}}{2}

e x t re m e - lo g_{5} (x)

e x t re m e f (x, y) = x^{3} - 2 x y + y^{2} + 4

e x t re m e f (x, y) = (x - y) (25 - x y)

e x t re m e \frac{e ^{- x}}{( 1 + e ^{- x} ) ^{2}}