extreme f(x)=x(x^2-4)

Lösung

extrempunkte

f (x) = x (x^{2} - 4)

Maximum (- \frac{2}{3}, \frac{16}{3 3}), Minimum (\frac{2}{3}, - \frac{16}{3 3})

Schritte zur Lösung

f^{'} (x) = (3 x + 2) (3 x - 2)

Intervalle finden:

Ansteigend

: - \infty < x < - \frac{2}{3},

Absteigend

: - \frac{2}{3} < x < \frac{2}{3},

Ansteigend

: \frac{2}{3} < x < \infty

Stecke

x = - \frac{2}{3}

x (x^{2} - 4) : \frac{16}{3 3}

Maximum (- \frac{2}{3}, \frac{16}{3 3})

Stecke

x = \frac{2}{3}

x (x^{2} - 4) : - \frac{16}{3 3}

Minimum (\frac{2}{3}, - \frac{16}{3 3})

Maximum (- \frac{2}{3}, \frac{16}{3 3}), Minimum (\frac{2}{3}, - \frac{16}{3 3})

e x t re m e 6 sinh (3 x) cosh (3 x)

e x t re m e f (x) = \frac{- 2 ( x ^{2} - 1 )}{x ^{2} - 4}

e x t re m e f (x, y) = \frac{e ^{2 - x y}}{x + y ^{2}}

e x t re m e f (x) = \frac{- 7}{x ^{2} - 9}

e x t re m e f (x, y) = 2 x^{2} + 3 y^{2} - 4 x - 3 y - 10