What is the extreme f(x)=-x^3+3x-7 ?

The extreme f(x)=-x^3+3x-7 is Minimum(-1,-9),Maximum(1,-5)

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extreme f(x)=-x^3+3x-7

extreme points

f (x) = - x^{3} + 3 x - 7

Minimum (- 1, - 9), Maximum (1, - 5)

Solution steps

f^{'} (x) = - 3 x^{2} + 3

Find intervals:

Decreasing

: - \infty < x < - 1,

Increasing

: - 1 < x < 1,

Decreasing

: 1 < x < \infty

Plug

x = - 1

into

- x^{3} + 3 x - 7 : - 9

Minimum (- 1, - 9)

Plug

x = 1

into

- x^{3} + 3 x - 7 : - 5

Maximum (1, - 5)

Minimum (- 1, - 9), Maximum (1, - 5)

What is the extreme f(x)=-x^3+3x-7 ?
The extreme f(x)=-x^3+3x-7 is Minimum(-1,-9),Maximum(1,-5)