What is the extreme f(x)=(x^2)/2+1/3 x ?

The extreme f(x)=(x^2)/2+1/3 x is Minimum(-1/3 ,-1/18)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

extreme f(x)=(x^2)/2+1/3 x

extreme points

f (x) = \frac{x ^{2}}{2} + \frac{1}{3} x

Minimum (- \frac{1}{3}, - \frac{1}{18})

Solution steps

f^{'} (x) = x + \frac{1}{3}

Find intervals:

Decreasing

: - \infty < x < - \frac{1}{3},

Increasing

: - \frac{1}{3} < x < \infty

Plug

x = - \frac{1}{3}

into

\frac{x ^{2}}{2} + \frac{1}{3} x : - \frac{1}{18}

Minimum (- \frac{1}{3}, - \frac{1}{18})

What is the extreme f(x)=(x^2)/2+1/3 x ?
The extreme f(x)=(x^2)/2+1/3 x is Minimum(-1/3 ,-1/18)