What is the domain of y=(x^2+1)/(x+1) ?

The domain of y=(x^2+1)/(x+1) is x -1

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domain of y=(x^2+1)/(x+1)

domain

y = \frac{x ^{2} + 1}{x + 1}

x < - 1 or x > - 1

Interval Notation

(- \infty, - 1) \cup (- 1, \infty)

Solution steps

Find undefined (singularity) points:

x = - 1

The function domain

x < - 1 or x > - 1

y = - \frac{1}{2} x^{2} + 4 x - 2

(2.8, 1.1), (- 3.4, 5.7)

f (x) = (x + 4) e^{- 2 x}

f (x) = x^{8} (x - 4)^{7}

\frac{\frac{3}{x + 1} - 2}{\frac{1}{4} - \frac{2}{x ^{2} - 1}}

What is the domain of y=(x^2+1)/(x+1) ?
The domain of y=(x^2+1)/(x+1) is x<-1\lor x>-1