What is the domain of (3/(x+1)-2)/(1/4-2/(x^2-1)) ?

The domain of (3/(x+1)-2)/(1/4-2/(x^2-1)) is x 3

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domain of (3/(x+1)-2)/(1/4-2/(x^2-1))

domain

\frac{\frac{3}{x + 1} - 2}{\frac{1}{4} - \frac{2}{x ^{2} - 1}}

x < - 3 or - 3 < x < - 1 or - 1 < x < 1 or 1 < x < 3 or x > 3

Interval Notation

(- \infty, - 3) \cup (- 3, - 1) \cup (- 1, 1) \cup (1, 3) \cup (3, \infty)

Solution steps

Find undefined (singularity) points:

x = 3, x = - 3, x = - 1, x = 1

The function domain

x < - 3 or - 3 < x < - 1 or - 1 < x < 1 or 1 < x < 3 or x > 3

sin (x)

\frac{5}{e ^{- x} - 5}

f (x) = \frac{6 x}{7 x - 3}

f (x) = \frac{x ^{2} + 2 x}{2 x ^{2} + 3 x - 2}

f (x) = x^{2} lo g_{e} (x)

What is the domain of (3/(x+1)-2)/(1/4-2/(x^2-1)) ?
The domain of (3/(x+1)-2)/(1/4-2/(x^2-1)) is x<-3\lor-3<x<-1\lor-1<x<1\lor 1<x<3\lor x>3