What is the critical f(x)=(x+4)e^{-2x} ?

The critical f(x)=(x+4)e^{-2x} is x=-7/2

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critical f(x)=(x+4)e^{-2x}

critical points

f (x) = (x + 4) e^{- 2 x}

x = - \frac{7}{2}

Solution steps

(x + 4) e^{- 2 x}

Find where

f^{'} (x)

is equal to zero or undefined

x = - \frac{7}{2}

Identify critical points not in

f (x)

domain

Domain of

(x + 4) e^{- 2 x} : - \infty < x < \infty

All critical points are in domain

x = - \frac{7}{2}

f (x) = x^{8} (x - 4)^{7}

\frac{\frac{3}{x + 1} - 2}{\frac{1}{4} - \frac{2}{x ^{2} - 1}}

sin (x)

\frac{5}{e ^{- x} - 5}

f (x) = \frac{6 x}{7 x - 3}

What is the critical f(x)=(x+4)e^{-2x} ?
The critical f(x)=(x+4)e^{-2x} is x=-7/2