What is the inverse of f(x)=ln(e^{x+1})+ln(2)-1 ?

The inverse of f(x)=ln(e^{x+1})+ln(2)-1 is x-ln(2)

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inverse of f(x)=ln(e^{x+1})+ln(2)-1

inverse

f (x) = ln (e^{x + 1}) + ln (2) - 1

x - ln (2)

Solution steps

y = ln (e^{x + 1}) + ln (2) - 1

Replace

x

with

y

x = ln (e^{y + 1}) + ln (2) - 1

Solve for

y, x = ln (e^{y + 1}) + ln (2) - 1

x - ln (2)

(8.2) (3.8)

f (x) = \frac{1}{x - 2} - 3

tan (\frac{π x}{4} + \frac{3 π}{4})

3 (x + 5) + 4

f (x) = \frac{x}{x + 1}

What is the inverse of f(x)=ln(e^{x+1})+ln(2)-1 ?
The inverse of f(x)=ln(e^{x+1})+ln(2)-1 is x-ln(2)