What is the domain of 3(sqrt(x+5))+4 ?

The domain of 3(sqrt(x+5))+4 is x>=-5

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domain of 3(sqrt(x+5))+4

domain

3 (x + 5) + 4

x \geq - 5

Interval Notation

[- 5, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 5

The function domain

x \geq - 5

f (x) = \frac{x}{x + 1}

f (x) = 2 x + 2

9 x^{2} - x^{3} - 3

y = 2 x - 4

f (x) = \frac{x + 3}{x ( x - 1 )}