What is the range of f(x)= x/(x+1) ?

The range of f(x)= x/(x+1) is f(x) 1

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range of f(x)= x/(x+1)

range

f (x) = \frac{x}{x + 1}

f (x) < 1 or f (x) > 1

Interval Notation

(- \infty, 1) \cup (1, \infty)

Solution steps

The function range is the combined domain of the inverse functions

Find the inverse function(s) of:

\frac{x}{x + 1}

Inverse of

\frac{x}{x + 1} : - \frac{x}{x - 1}

- \frac{x}{x - 1}

Find the domain of each inverse function

Domain of

- \frac{x}{x - 1} : x < 1 or x > 1

Combine the intervals

f (x) < 1 or f (x) > 1

f (x) = 2 x + 2

9 x^{2} - x^{3} - 3

y = 2 x - 4

f (x) = \frac{x + 3}{x ( x - 1 )}

f (x) = \frac{3 x ^{2} - 1}{∣ x + 3 ∣ + 2}

What is the range of f(x)= x/(x+1) ?
The range of f(x)= x/(x+1) is f(x)<1\lor f(x)>1