What is the domain of 1/(sqrt(x)-5) ?

The domain of 1/(sqrt(x)-5) is 0 25

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domain of 1/(sqrt(x)-5)

domain

\frac{1}{x - 5}

0 \leq x < 25 or x > 25

Interval Notation

[0, 25) \cup (25, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 0

Find undefined (singularity) points:

x = 25

Combine real regions and undefined points for final function domain

0 \leq x < 25 or x > 25

f (x) = \frac{4 x + 3}{2 x + 5}

f (x) = b^{x}

f (x) = x^{4} - 98 x^{2} + 1

f (x) = x ∣ x + 4 ∣

f (x) = - 3 (x - 1)^{2} (x^{2} - 4)

What is the domain of 1/(sqrt(x)-5) ?
The domain of 1/(sqrt(x)-5) is 0<= x<25\lor x>25