What is the inverse of f(x)=sqrt((4x+3)/(2x+5)) ?

The inverse of f(x)=sqrt((4x+3)/(2x+5)) is (3-5x^2)/(2(x^2-2))

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inverse of f(x)=sqrt((4x+3)/(2x+5))

inverse

f (x) = \frac{4 x + 3}{2 x + 5}

\frac{3 - 5 x ^{2}}{2 ( x ^{2} - 2 )}

Solution steps

y = \frac{4 x + 3}{2 x + 5}

Replace

x

with

y

x = \frac{4 y + 3}{2 y + 5}

Solve for

y, x = \frac{4 y + 3}{2 y + 5}

\frac{3 - 5 x ^{2}}{2 ( x ^{2} - 2 )}

f (x) = b^{x}

f (x) = x^{4} - 98 x^{2} + 1

f (x) = x ∣ x + 4 ∣

f (x) = - 3 (x - 1)^{2} (x^{2} - 4)

f (x) = x^{3} + 2 x

What is the inverse of f(x)=sqrt((4x+3)/(2x+5)) ?
The inverse of f(x)=sqrt((4x+3)/(2x+5)) is (3-5x^2)/(2(x^2-2))