What is the extreme f(x)=x^4-98x^2+1 ?

The extreme f(x)=x^4-98x^2+1 is Minimum(-7,-2400),Maximum(0,1),Minimum(7,-2400)

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extreme f(x)=x^4-98x^2+1

extreme

Minimum (- 7, - 2400), Maximum (0, 1), Minimum (7, - 2400)

Solution steps

f^{'} (x) = 4 x^{3} - 196 x

Find intervals:

Decreasing

: - \infty < x < - 7,

Increasing

: - 7 < x < 0,

Decreasing

: 0 < x < 7,

Increasing

: 7 < x < \infty

Plug

x = - 7

into

x^{4} - 98 x^{2} + 1 : - 2400

Minimum (- 7, - 2400)

Plug

x = 0

into

x^{4} - 98 x^{2} + 1 : 1

Maximum (0, 1)

Plug

x = 7

into

x^{4} - 98 x^{2} + 1 : - 2400

Minimum (7, - 2400)

Minimum (- 7, - 2400), Maximum (0, 1), Minimum (7, - 2400)

What is the extreme f(x)=x^4-98x^2+1 ?
The extreme f(x)=x^4-98x^2+1 is Minimum(-7,-2400),Maximum(0,1),Minimum(7,-2400)