What is the asymptotes of f(x)= 4/(x^2+2x-8) ?

The asymptotes of f(x)= 4/(x^2+2x-8) is Vertical: x=-4,x=2,Horizontal: y=0

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asymptotes of f(x)= 4/(x^2+2x-8)

asymptotes

f (x) = \frac{4}{x ^{2} + 2 x - 8}

Vertical : x = - 4, x = 2, Horizontal : y = 0

Solution steps

Vertical asymptotes of

\frac{4}{x ^{2} + 2 x - 8} : x = - 4, x = 2

Horizontal Asymptotes of

\frac{4}{x ^{2} + 2 x - 8} : y = 0

Slant Asymptotes of

\frac{4}{x ^{2} + 2 x - 8} :

None

Vertical : x = - 4, x = 2, Horizontal : y = 0

y = - x + 1 - 3

f (x) = x^{(\frac{7}{2})} - 7 x^{2}

2 y = x - 3, (- 1, 2)

f (x) = \frac{3 x}{x ^{2} - 25}

- \frac{1}{2} x^{4} - 6 x^{3} - 72 x^{2}

What is the asymptotes of f(x)= 4/(x^2+2x-8) ?
The asymptotes of f(x)= 4/(x^2+2x-8) is Vertical: x=-4,x=2,Horizontal: y=0