What is the critical f(x)=x^{(7/2)}-7x^2 ?

The critical f(x)=x^{(7/2)}-7x^2 is x=0,x=2^{4/3}

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critical f(x)=x^{(7/2)}-7x^2

critical

x = 0, x = 2^{\frac{4}{3}}

Solution steps

x^{\frac{7}{2}} - 7 x^{2}

Find where

f^{'} (x)

is equal to zero or undefined

x = 0, x = 2^{\frac{4}{3}}

Identify critical points not in

f (x)

domain

Domain of

x^{\frac{7}{2}} - 7 x^{2} : x \geq 0

All critical points are in domain

x = 0, x = 2^{\frac{4}{3}}

What is the critical f(x)=x^{(7/2)}-7x^2 ?
The critical f(x)=x^{(7/2)}-7x^2 is x=0,x=2^{4/3}