What is the perpendicular 2y=x-3,(-1,2) ?

The perpendicular 2y=x-3,(-1,2) is y=-2x

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perpendicular 2y=x-3,(-1,2)

perpendicular

2 y = x - 3, (- 1, 2)

y = - 2 x

Solution steps

Find the line

y = mx + b

perpendicular to

2 y = x - 3

that passes through

(- 1, 2)

Find the slope of

2 y = x - 3 : m = \frac{1}{2}

Compute the slope of the perpendicular line:

m_{p} = - 2

Find the line with slope m=

- 2

and passing through

(- 1, 2) : y = - 2 x

y = - 2 x

f (x) = \frac{3 x}{x ^{2} - 25}

- \frac{1}{2} x^{4} - 6 x^{3} - 72 x^{2}

f (x) = 3 x - 14

\frac{a - \frac{2 a - 1}{a}}{\frac{1 - a}{3 a}}

f (x) = x^{2} + 2

What is the perpendicular 2y=x-3,(-1,2) ?
The perpendicular 2y=x-3,(-1,2) is y=-2x