What is the extreme f(x)=x^2e^{-7x} ?

The extreme f(x)=x^2e^{-7x} is Minimum(0,0),Maximum(2/7 , 4/(49e^2))

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extreme f(x)=x^2e^{-7x}

extreme

Minimum (0, 0), Maximum (\frac{2}{7}, \frac{4}{49 e ^{2}})

Solution steps

f^{'} (x) = e^{- 7 x} x (2 - 7 x)

Find intervals:

Decreasing

: - \infty < x < 0,

Increasing

: 0 < x < \frac{2}{7},

Decreasing

: \frac{2}{7} < x < \infty

Plug

x = 0

into

x^{2} e^{- 7 x} : 0

Minimum (0, 0)

Plug

x = \frac{2}{7}

into

x^{2} e^{- 7 x} : \frac{4}{49 e ^{2}}

Maximum (\frac{2}{7}, \frac{4}{49 e ^{2}})

Minimum (0, 0), Maximum (\frac{2}{7}, \frac{4}{49 e ^{2}})

What is the extreme f(x)=x^2e^{-7x} ?
The extreme f(x)=x^2e^{-7x} is Minimum(0,0),Maximum(2/7 , 4/(49e^2))