What is the perpendicular y=2x+3,\at 1,2 ?

The perpendicular y=2x+3,\at 1,2 is y=-1/2 x+b

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perpendicular y=2x+3,\at 1,2

perpendicular

y = 2 x + 3, at 1, 2

y = - \frac{1}{2} x + b

Solution steps

Find the slope of

y = 2 x + 3 : m = 2

Compute the slope of the perpendicular line:

m_{p} = - \frac{1}{2}

Line with slope m=

- \frac{1}{2} : y = - \frac{1}{2} x + b

y = - \frac{1}{2} x + b

f (x) = x - \frac{1}{x}

\frac{2}{x - 6} + 4

(x + 3)^{2} - 1

- \frac{1}{2} x^{4} + 48 x^{2}

y = \frac{1}{4} x + 9, at (2 - 2)

What is the perpendicular y=2x+3,\at 1,2 ?
The perpendicular y=2x+3,\at 1,2 is y=-1/2 x+b