What is the perpendicular y= 1/4 x+9,\at (2-2) ?

The perpendicular y= 1/4 x+9,\at (2-2) is y=-4x+b

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perpendicular y= 1/4 x+9,\at (2-2)

perpendicular

y = \frac{1}{4} x + 9, at (2 - 2)

y = - 4 x + b

Solution steps

Find the slope of

y = \frac{1}{4} x + 9 : m = \frac{1}{4}

Compute the slope of the perpendicular line:

m_{p} = - 4

Line with slope m=

- 4 : y = - 4 x + b

y = - 4 x + b

f (x) = \frac{( - 4 x ^{2} - 2 x + 1 )}{2 x + 3}

f (x) = \frac{1}{2 x - 8}

f (x) = \frac{- 4 x ^{2} - 3 x + 8}{x + 1}

x - 1, x < 0

f (x) = 3 x^{4} - 4 x^{3}

What is the perpendicular y= 1/4 x+9,\at (2-2) ?
The perpendicular y= 1/4 x+9,\at (2-2) is y=-4x+b