What is the inverse of f(x)=-3+sqrt(9-x^2) ?

The inverse of f(x)=-3+sqrt(9-x^2) is sqrt(-x^2-6x),-sqrt(-x^2-6x)

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inverse of f(x)=-3+sqrt(9-x^2)

inverse

f (x) = - 3 + 9 - x^{2}

- x^{2} - 6 x, - - x^{2} - 6 x

Solution steps

y = - 3 + 9 - x^{2}

Replace

x

with

y

x = - 3 + 9 - y^{2}

Solve for

y, x = - 3 + 9 - y^{2}

- x^{2} - 6 x, - - x^{2} - 6 x

f (x) = \frac{x ^{2} - 6 x + 12}{x - 4}

6 x + y = - 1

7 - 2 x + 2

f (x) = sin (2 (x + π))

y = 6 - x - 4 x^{2} - x^{3}

What is the inverse of f(x)=-3+sqrt(9-x^2) ?
The inverse of f(x)=-3+sqrt(9-x^2) is sqrt(-x^2-6x),-sqrt(-x^2-6x)