What is the shift f(x)=sin(2(x+pi)) ?

The shift f(x)=sin(2(x+pi)) is Phase:-pi, Vertical:0

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shift f(x)=sin(2(x+pi))

shift

f (x) = sin (2 (x + π))

Phase : - π, Vertical : 0

Solution steps

f (x) = sin (2 (x + π))

g (B x - C) = sin (2 (x + π)), B = 2, C = - 2 π, D = 0

Therefore, the phase shift

\frac{C}{B}

\frac{- 2 π}{2}

- π

The vertical shift

D

0

0

y = 6 - x - 4 x^{2} - x^{3}

f (x) = \frac{x - 7}{5 x ^{2}}

f (x) = \frac{3 x - 9}{x ^{2} - 6 x + 9}

f (x) = \frac{3}{5} x - 12

\frac{2 x ^{2} + 16 x - 18}{x ^{2} + x - 6}

What is the shift f(x)=sin(2(x+pi)) ?
The shift f(x)=sin(2(x+pi)) is Phase:-pi, Vertical:0