What is the domain of y=sqrt(6-x-4x^2-x^3) ?

The domain of y=sqrt(6-x-4x^2-x^3) is x<=-3\lor-2<= x<= 1

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domain of y=sqrt(6-x-4x^2-x^3)

domain

y = 6 - x - 4 x^{2} - x^{3}

x \leq - 3 or - 2 \leq x \leq 1

Solution steps

Find non-negative values for radicals:

x \leq - 3 or - 2 \leq x \leq 1

The function domain

x \leq - 3 or - 2 \leq x \leq 1

f (x) = \frac{x - 7}{5 x ^{2}}

f (x) = \frac{3 x - 9}{x ^{2} - 6 x + 9}

f (x) = \frac{3}{5} x - 12

\frac{2 x ^{2} + 16 x - 18}{x ^{2} + x - 6}

3 cos (x - \frac{π}{4}) - 1

What is the domain of y=sqrt(6-x-4x^2-x^3) ?
The domain of y=sqrt(6-x-4x^2-x^3) is x<=-3\lor-2<= x<= 1