What is the extreme f(x,y)=x^2-3y^2-8x+9y+3xy ?

The extreme f(x,y)=x^2-3y^2-8x+9y+3xy is Saddle(1,2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

extreme f(x,y)=x^2-3y^2-8x+9y+3xy

extreme points

f (x, y) = x^{2} - 3 y^{2} - 8 x + 9 y + 3 x y

Saddle (1, 2)

Solution steps

Find the critical points:

(1, 2)

\frac{\partial ^{2} f}{\partial x ^{2}} = - 6

D (x, y) = - 21

Check the sign of at each critical point

Check critical point

(1, 2) :

Saddle

Saddle (1, 2)

f (d, y) = \frac{d}{d ^{2}} (y)

y = - 5 cos (3 x) - 2

f (x, y) = 3 x^{\frac{1}{3}} y^{\frac{1}{3}}

f (x) = \frac{x ^{2}}{x - 1}

P (- 8.5) Q (- 4.11)

What is the extreme f(x,y)=x^2-3y^2-8x+9y+3xy ?
The extreme f(x,y)=x^2-3y^2-8x+9y+3xy is Saddle(1,2)