What is the extreme f(x,y)=3x^{1/3}y^{1/3} ?

The extreme f(x,y)=3x^{1/3}y^{1/3} is None

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extreme f(x,y)=3x^{1/3}y^{1/3}

extreme points

f (x, y) = 3 x^{\frac{1}{3}} y^{\frac{1}{3}}

None

Solution steps

Find the critical points:

None

3 x^{\frac{1}{3}} y^{\frac{1}{3}}

has no critical points, therefore there are no extreme points

None

f (x) = \frac{x ^{2}}{x - 1}

P (- 8.5) Q (- 4.11)

x^{3} + 8 x^{2} - 6 x - 4

f (x) = - \frac{13}{9} x^{2} + \frac{8}{3} x^{2} + \frac{37}{10}

\frac{( x - 4 )}{x ^{2}}

What is the extreme f(x,y)=3x^{1/3}y^{1/3} ?
The extreme f(x,y)=3x^{1/3}y^{1/3} is None