What is the extreme f(x)=x^{3/4}-2x^{3/4} ?

The extreme f(x)=x^{3/4}-2x^{3/4} is Maximum(0,0)

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extreme f(x)=x^{3/4}-2x^{3/4}

extreme points

f (x) = x^{\frac{3}{4}} - 2 x^{\frac{3}{4}}

Maximum (0, 0)

Solution steps

f^{'} (x) = - \frac{3}{4 x ^{\frac{1}{4}}}

Find intervals:

Decreasing

: 0 < x < \infty

Plug

x = 0

into

x^{\frac{3}{4}} - 2 x^{\frac{3}{4}} : 0

Maximum (0, 0)

f (x) = x^{\frac{2}{3}} (x - 6)

\frac{16 a ^{4} + 16 a}{a ^{2} + 1 - a}

f (x) = - 2 x^{2} - 5 x y - 6 y^{2} + 32 x + 63 y + 9

f (x) = 4 sin (x) - 3 cos (x)

y = (\frac{I x + 2 I - 1}{2 x + 3}) e^{2 x}

What is the extreme f(x)=x^{3/4}-2x^{3/4} ?
The extreme f(x)=x^{3/4}-2x^{3/4} is Maximum(0,0)